3a-[3+2(a-1)]=0

Solution for 3a-[3+2(a-1)]=0 equation:

Simplifying
3a + -1[3 + 2(a + -1)] = 0

Reorder the terms:
3a + -1[3 + 2(-1 + a)] = 0
3a + -1[3 + (-1 * 2 + a * 2)] = 0
3a + -1[3 + (-2 + 2a)] = 0

Combine like terms: 3 + -2 = 1
3a + -1[1 + 2a] = 0
3a + [1 * -1 + 2a * -1] = 0
3a + [-1 + -2a] = 0

Reorder the terms:
-1 + 3a + -2a = 0

Combine like terms: 3a + -2a = 1a
-1 + 1a = 0

Solving
-1 + 1a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1a = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 1a = 0 + 1
1a = 0 + 1

Combine like terms: 0 + 1 = 1
1a = 1

Divide each side by '1'.
a = 1

Simplifying
a = 1